|www.nortonkit.com||18 अक्तूबर 2013|
|Digital | Logic Families | Digital Experiments | Analog | Analog Experiments | DC Theory | AC Theory | Optics | Computers | Semiconductors | Test HTML|
|Direct links to other pages:|
|Basic Summing:||[Setting the Gain Coefficient] [Analog Addition] [Adding a Fixed Constant]|
|Variations in Feedback Circuits:||[Integrators] [Differentiators] [Logarithmic Amplifiers] [Non-Inverting Amplifiers] [A Difference Amplifier] [Increasing the Output Current Capacity] [A Half-Wave Rectifier] [A Full-Wave Rectifier]|
|Mixing Analog and Digital Technologies:||[Comparators] [Digital to Analog Conversion] [Analog to Digital Conversion]|
|Generating Waveforms:||[A Square Wave Generator] [A Triangle Wave Generator] [A Sine Wave Generator]|
|Operational Amplifiers:||[Characteristics of Operational Amplifiers] [Inside the 741]|
As we have said, the choice of the feedback element used with an operational amplifier has much to do with the behavior of the circuit. Therefore, we should explore what happens if we use different types of feedback components. In this example, we'll replace the feedback resistor with a capacitor and note the results.
In the circuit shown to the right, we have replaced the feedback resistor with a capacitor. Therefore, any feedback current must be based on a change in output voltage. As feedback current flows, the capacitor will gain an electric charge, which will change according to the cumulative effects of the output signal.
If the input voltage is zero, no input current will flow. Therefore no feedback current can flow and the output voltage will remain constant. If the input voltage is non-zero, the basic equation for the output voltage becomes Vout = -Vin/RC + K, where R is the input resistance in ohms, C is the feedback capacitance in farads, and K is a fixed constant representing the accumulated voltage from the past.
If the input voltage is constantly changing, the output voltage at any instant will be the integral of all past input voltage values. For example, a bipolar sine wave input will actually produce another sine wave as its output, at a phase angle of 90° from the input sine wave. Technically, the output will be an inverted cosine wave.
A couple of factors are of interest with these circuits:
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